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NumericRange[Long] doesn't support ranges with more than Int.MaxValue values #5619

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scabug opened this issue Mar 27, 2012 · 2 comments
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NumericRange[Long] doesn't support ranges with more than Int.MaxValue values #5619

scabug opened this issue Mar 27, 2012 · 2 comments
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enhancement won't fix

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@scabug
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scabug commented Mar 27, 2012

The title pretty much says it all. As soon as any caller invokes count() - at some indefinite time after construction - a NumericRange[Long] with a long range throws an IllegalArgumentException.

count() is used very ubiquitously in the implementation of the class - even in toString() - so it's not really avoidable.

I know the current behavior is by design... but would it break a lot of things if count()/length() returned a Long?

FWIW, this was driven by StackOverflow post http://stackoverflow.com/questions/9888706 .
@scabug
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scabug commented Mar 27, 2012

Imported From: https://issues.scala-lang.org/browse/SI-5619?orig=1
Reporter: Ed Staub (estaub)
Affected Versions: 2.9.1
See #5622

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scabug commented Mar 27, 2012

@dcsobral said:
It would break things, it would preclude array-based implementations, and it would impose a performance penalty on anything that used indices.

@scabug scabug closed this as completed Jun 11, 2012
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